WebDivide 16 into two parts such that twice the square of the larger part exceeds the square of the smaller part by 164. Solution: Let larger part be x, therefore the smaller part =16−x Given : 2x2−(16−x)2=164 ⇒2x2−(256+x2−32x)−164=0 i.e. 22x−256−x2+32x−164=0 ⇒x2+32x−420=0 On factorizing, it gives : (x+42)(x−10)=0 WebApr 11, 2024 · a) Divide 16 into two parts such that twice the square of the larger part exceeds the square of the smaller part by 164. [3] b) Find the amount of bill for the following intra − state transaction of goods. The rate of GST is 12%. c) A man from the top of a vertical tower observes a car moving at a uniform speed coming directly towards him.

10th Quadratic Equation Word Problemswith Answer-4

WebDivide 16 into two parts such that twice the square of the larger part exceeds the square of the smaller part by 164 . CBSE, Class 10, Exercise 10e, Maths, Quadratic Equations, RS Aggarwal. ... Divide 57 into two parts whose product is 680 . … WebProblem 4. Divide 48 into two such parts, that if the less be divided by 4, and the greater by 6, the sum of the quotients will be 9. Here, if x be put for the smaller part, the greater will be 48 - x. By the conditions of the problem x/4 + (48 - x)/6 = 9. Therefore x = 12, the less. And 48 - x = 36, the greater. blackberry\u0027s pl

QUADRATIC EQUATIONS - lfsatcontent.blob.core.windows.net

WebLet x and (16 - x) are two parts of 16 where (16 - x) is longer and x is smaller. According to the question, 2 × square of longer = square of smaller + 164 WebAug 19, 2024 · Divide 16 into two parts such that twice the square of larger part exceeds the square smaller part by 164.#QuadraticEquation #Class10#CBSE#Mathematics#Higher... WebAug 19, 2024 · Divide 16 into two parts such that twice the square of larger part exceeds the square smaller part by 164.#QuadraticEquation #Class10#CBSE#Mathematics#Higher... galaxy on7 insert sim card problem